Which of the following phenomena does not explain by wave nature of light. A. reflection B. diffraction C. photoelectric effect D. interference E. polarization Choose the most appropriate answer from the options given below:

In photoelectric experiment energy of $$2.48\mathrm{eV}$$ irradiates a photo sensitive material. The stopping potential was measured to be $$0.5\mathrm{V}$$. Work function of the photo sensitive material is :

The magnetic moment of a bar magnet is $$0.5{\mathrm{Am}}^2$$. It is suspended in a uniform magnetic field of $$8\times 10^{-2}\mathrm{T}$$. The work done in rotating it from its most stable to most unstable position is:

Paramagnetic substances: A. align themselves along the directions of external magnetic field. B. attract strongly towards external magnetic field. C. has susceptibility little more than zero. D. move from a region of strong magnetic field to weak magnetic field. Choose the most appropriate answer from the options given below:

Match List I with List II: .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-c3ow{border-color:inherit;text-align:center;vertical-align:top} .tg .tg-7btt{border-color:inherit;font-weight:bold;text-align:center;vertical-align:top} .tg .tg-0pky{border-color:inherit;text-align:left;vertical-align:top} LIST I (Y vs X) LIST II (Shape of Graph) A. Y-magnetic susceptibility X = magnetising field I. B. Y = magnetic field X = distance from centre of a current carrying wire for x \mathrm{a}$$(where$$\mathrm{a}=$$ radius of wire) III. D. Y = magnetic field inside solenoid X = distance from centre IV. Choose the correct answer from the options given below :

A light planet is revolving around a massive star in a circular orbit of radius $\mathrm{R}$ with a period of revolution T. If the force of attraction between planet and star is proportional to ${\mathrm{R}}^{-3/2}$ then choose the correct option :

If $\mathrm{R}$ is the radius of the earth and the acceleration due to gravity on the surface of earth is $g={\pi }^2\mathrm{m}/{\mathrm{s}}^2$, then the length of the second's pendulum at a height $\mathrm{h}=2R$ from the surface of earth will be, :

The acceleration due to gravity on the surface of earth is $$\mathrm{g}$$. If the diameter of earth reduces to half of its original value and mass remains constant, then acceleration due to gravity on the surface of earth would be :

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The angular speed of the moon in its orbit about the earth is more than the angular speed of the earth in its orbit about the sun. Reason (R) : The moon takes less time to move around the earth than the time taken by the earth to move around the sun. In the light of the above statements, choose the most appropriate answer from the options given below :

The mass of the moon is $$\frac{1}{144}$$ times the mass of a planet and its diameter is $$\frac{1}{16}$$ times the diameter of a planet. If the escape velocity on the planet is $$v$$, the escape velocity on the moon will be :

Four identical particles of mass $$m$$ are kept at the four corners of a square. If the gravitational force exerted on one of the masses by the other masses is $$\left(\frac{2\sqrt{2}+1}{32}\right)\frac{{\mathrm{Gm}}^2}{L^2}$$, the length of the sides of the square is

At what distance above and below the surface of the earth a body will have same weight. (take radius of earth as $$R$$.)

A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution :

Escape velocity of a body from earth is $$11.2\mathrm{km}/\mathrm{s}$$. If the radius of a planet be onethird the radius of earth and mass be one-sixth that of earth, the escape velocity from the planet is :

The gravitational potential at a point above the surface of earth is $$-5.12\times 10^7\mathrm{J}/\mathrm{kg}$$ and the acceleration due to gravity at that point is $$6.4\mathrm{m}/{\mathrm{s}}^2$$. Assume that the mean radius of earth to be $$6400\mathrm{km}$$. The height of this point above the earth's surface is :

A satellite of $$10^3\mathrm{kg}$$ mass is revolving in circular orbit of radius $$2R$$. If $$\frac{10^{4}R}{6}\mathrm{J}$$ energy is supplied to the satellite, it would revolve in a new circular orbit of radius (use $$g=10\mathrm{m}/{\mathrm{s}}^2,R=$$ radius of earth)

An astronaut takes a ball of mass $$m$$ from earth to space. He throws the ball into a circular orbit about earth at an altitude of $$318.5\mathrm{km}$$. From earth's surface to the orbit, the change in total mechanical energy of the ball is $$x\frac{{\mathrm{GM}}_{\mathrm{e}}\mathrm{m}}{21{\mathrm{R}}_{\mathrm{e}}}$$. The value of $$x$$ is (take $${\mathrm{R}}_{\mathrm{e}}=6370\mathrm{km})$$ :

A metal wire of uniform mass density having length $$L$$ and mass $$M$$ is bent to form a semicircular arc and a particle of mass $$\mathrm{m}$$ is placed at the centre of the arc. The gravitational force on the particle by the wire is :

A $$90\mathrm{kg}$$ body placed at $$2\mathrm{R}$$ distance from surface of earth experiences gravitational pull of : ($$\mathrm{R}=$$ Radius of earth, $$\mathrm{g}=10\mathrm{m}{\mathrm{s}}^{-2}$$)

Correct formula for height of a satellite from earths surface is :