Mathematics3d-geometry2017medium
If the line, {{x - 3} \over 1} = {{y + 2} \over { - 1}} = {{z + \lambda } \over { - 2}} lies in the plane, 2x−4y+3z=2, then the shortest distance between this line and the line, {{x - 1} \over {12}} = {y \over 9} = {z \over 4} is :