The statement that is INCORRECT about the interstitial compounds is :

$$\underline{A}\text{buildrel}4KOH,O_2\frac{⟶}{}\underset{\left(Green\right)}{2\underline{B}}+2H_{2}O$$ $$3\underline{B}\text{buildrel}4HCl\frac{⟶}{}\underset{\left(Purple\right)}{2\underline{C}}+Mn{O}_2+2H_{2}O$$ $$2\underline{C}\text{buildrel}{H}_{2}O.KI\frac{⟶}{}\underset{\left(Purple\right)}{2\underline{A}}+2KOH+\underline{D}$$ In the above sequence of reactions, $$\underline{A}$$ and $$\underline{D}$$, respectively, are :

The correct order of atomic radii is :

Wilkinson catalyst is : (Et = C2H5)

The effect of lanthanoid contraction in the lanthanoid series of elements by and large means :

The transition element that has lowest enthalpy of atomisation, is :

The element that usually does NOT show variable oxidation states is :

The 71st electron of an element X with an atomic number of 71 enters into the orbital :

The ion that has sp3d2 hybridization for the central atom, is :

The correct statement among the following is :

The oxoacid of sulphur that does not contain bond between sulphur atoms is

During the change of O2 to O2- , the incoming electron goes to the orbital :

HF has highest boiling point among hydrogen halides, because it has :

Among the following species, the diamagnetic molecule is

Among the following, the molecule expected to be stabilized by anion formation is : C2, O2, NO, F2

The correct statement about ICl5 and $$IC{l}_4^{-}$$ is

Among the following molecules / ions, $$C_2^{2-},N_2^{2-},O_2^{2-},O_2$$ which one is diamagnetic and has the shortest bond length?

The covalent alkaline earth metal halide (X = Cl, Br, I) is :

The pair that contains two P – H bonds in each of the oxoacids is

The type of hybridisation and number of lone pair (s) of electrons of Xe in XeOF4, respectively, are: