1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, {{\Delta {T_b}(A)} \over {\Delta {T_b}(B)}}, is :

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be. (molar mass of urea = 60 g mol–1)

Molal depression constant for a solvent is 4.0 kg mol–1. The depression in the freezing point of the solvent for 0.03 mol kg–1 solution of K2SO4 is : (Assume complete dissociation of the electrolyte)

Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressures of pure liquids 'M' and 'N' are 450 and 700 mmHg, respectively, at the same temperature. Then correct statement is: (xM = Mole fraction of 'M' in solution ; xN = Mole fraction of 'N' in solution ; yM = Mole fraction of 'M' in vapour phase ; yN = Mole fraction of 'N' in vapour phase)

The osmotic pressure of a dilute solution of an ionic compound XY in water is four times that of a solution of 0.01 M BaCl2 in water. Assuming complete dissociation of the given ionic compounds in water, the concentration of XY (in mol L–1) in solution is :

For the solution of the gases w, x, y and z in water at 298K, the Henrys law constants (KH) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is :-

The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K on mixing the two liquids, the sum of their initial volume is equal ot the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture, The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are :

Freezing point of a 4% aqueous solution of X is equal to freezing point of 12% aqueous solution of Y. If molecular weight of X is A, then molecular weight of Y is -

Molecules of benzoic acid (C6H5COOH) dimerise in benzene. 'w' g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2K. If the percentage association of the acid to form dimmer in the solution is 80, then w is – (Its given that Kf = 5 K kg mol–1, Molar mass of benzoic acid = 122 g mol–1)

Which one of the following statements regarding Henry's law is not correct ?

A solution containing 62 g ethylene glycol in 250 g water is cooled to $$-$$ 10oC. If Kf for water is 1.86 K kg mol$$-$$1 , the amount of water (in g) separated as ice is :

Liquids A and B form an ideal solution in the entire composition range. At 350 K, the vaapor pressures of pure A and pure B are 7 $$\times$$ 103 Pa and 12 $$\times$$ 103 Pa, respectively . The composition of the vapor in equilibriumwith a solution containing 40 mole percent of A at this temperature is :

The freezing point of a diluted milk sample is found to be –0.2oC, while it should have been –0.5oC for pure milk. How much water has been added to pure milk to make the diluted sample?

K2Hgl4 is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is:

Elevation in the boiling point for 1 molar solution of glucose is 2 K. The depression in the freezing point for 2 molal solution of glucose in the same solvent is 2 K. The relation between Kb and Kf is

In which one of the following equilibria, Kp $$\ne$$ KC ?

The INCORRECT match in the following is :

For the reaction, 2SO2(g) + O2(g) = 2SO3(g), $$\Delta$$H = –57.2 kJ mol–1 and KC = 1.7 × 1016 Which of the following statement is incorrect ?

Consider the reaction N2(g) + 3H2(g) $$\rightleftharpoons$$ 2NH3(g) The equilibrium constant of the above reaction is Kp. If pure ammonia is left to dissociate, the partial pressure of ammonia at equilibrium is given by (Assume that PNH3 << Ptotal at equilibrium)

For the following reactions, equilibrium constants are given : S(s) + O2(g) ⇋ SO2(g); K1 = 1052 2S(s) + 3O2(g) ⇋ 2SO3(g); K2 = 10129 The equilibrium constant for the reaction, 2SO2(g) + O2(g) ⇋ 2SO3(g) is :