Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is 16. The intensity of the waves are in the ratio :

In a Young’s double slit experiment with slit separation 0.1 mm, one observes a bright fringe at angle {1 \over {40}} by using light of wavelength $$\lambda$$1. When the light of wavelength $$\lambda$$2 is used a bright fringe is seen at the same angle in the same set up. Given that $$\lambda$$1 and $$\lambda$$2 are in visible range (380 nm to 740 nm), their values are -

In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength $$\lambda$$ = 500 nm is incident on the slits. The total number of bright fringes that are observed in the angular range $$-$$ 30o$$\le$$$$\theta$$$$\le$$30o is :

Consider a tank made of glass(refractive index 1.5) with a thick bottom. It is filled with a liquid of refractive index $$\mu$$. A student finds that, irrespective of what the incident angle i (see figure) is for a beam of light entering the liquid, the light reflected from the liquid glass interface is never completely polarized. For this to happen, the minimum value of $$\mu$$ is :

In an interference experiment the ratio of amplitudes of coherent waves is {{{a_1}} \over {{a_2}}} = {1 \over 3} . The ratio of maximum and minimum intensities of fringes will be :

A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :

In the given circuit, the charge on 4 $$\mu$$F capacitor will be :

Two identical parallel plate capacitors, of capacitance C each, have plates of area A, separated by a distance d. The space between the plates of the two capacitors, is filled with three dielectrics, of equal thickness and dielectric constants K1, K2 and K3. The first capacitor is filled as shown in fig.I, and the second one is filled as shown in fig II. If these two modified capacitors are charged by the same potential V, the ratio of the energy stored in the two, would be (E1 refers to capacitor (I) and E2 to capacitor (II)):

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are :

The parallel combination of two air filled parallel plate capacitors of capacitance C and nC is connected to a battery of voltage, V. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant K is placed between the two plates of the first capacitor. The new potential difference of the combined system is :-

A capacitor with capacitance 5μF is charged to 5μC. If the plates are pulled apart to reduce the capacitance to 2μF, how much work is done ?

Determine the charge on the capacitor in the following circuit :

A parallel plate capacitor has 1μF capacitance. One of its two plates is given +2μC charge and the other plate, +4μC charge. The potential difference developed across the capacitor is:-

Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of 106 V/m. The plate area is 10–4 m2. What is the dielectric constant is the capacitance is 15 pF? (given $$\epsilon$$0 = 8.86 × 10–12 C2/Nm2)

The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure : When is the value of current at t = 4 s ?

A parallel plate capacitor with plates of area 1 m2 each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge on each plate is : (Take $$\epsilon$$0 = 8.85 $$\times$$ 10$$-$$12 {{{C^2}} \over {N - {m^2}}})

In the figure shown, after the switch 'S' is turned from position 'A' to position 'B', the energy dissipated in the circuit in terms of capacitance 'C' and total charge 'Q' is :

Seven capacitors, each of capacitance 2 $$\mu$$F, are to be connected in a configuration to obtain an effective capacitance of \left( {{6 \over {13}}} \right)\mu F. Which of the combinations, shown in figures below, will achieve the desired value

In the figure shown below, the charge on the left plate of the 10$$\mu$$F capacitor is –30$$\mu$$C. The charge on the right plate of the 6 $$\mu$$F capacitor is :

A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates. The work done by the capacitor on the slab is :