A plane electromagnetic wave having a frequency v = 23.9 GHz propagates along the positive z-direction in free space. The peak value of the Electric Field is 60 V/m. Which among the following is the acceptable magnetic field component in the electromagnetic wave ?

An electromagnetic wave is represented by the electric field $$\overrightarrow{E}=E_0\hat{n}\sin \left[\omega t+\left(6y-8z\right)\right]$$ . Taking unit vectors in x, y and z directions to be $$\hat{i},\hat{j},\hat{k}$$ , the direction of propagation $$\hat{s}$$, is :

Light is incident normally on a completely absorbing surface with an energy flux of 25 W cm–2. If the surface has an area of 25 cm2, the momentum transferred to the surface in 40 min time duration will be :

The electric field of a plane electromagnetic wave is given by $$\overrightarrow{E}=E_0\hat{i}\cos (kz)cos(\omega t)$$ The corresponding magnetic field $$\overrightarrow{B}$$ is then given by

50 W/m2 energy density of sunlight is normally incident on the surface of a solar panel. Some part of incident energy (25%) is reflected from the surface and the rest is absorbed. The force exerted on 1m2 surface area will be close to (c = 3 × 108 m/s) :-

The magnetic field of a plane electromagnetic wave is given by : $\overline B = {B_0}\widehat i\left[ {\cos (kz - \omega t)} \right] + {B_i}\widehat j\cos (kz + \omega t)$ B0 = 3 × 10–5 T and B1 = 2 × 10–6 T. The rms value of the force experienced by a stationary charge Q = 10–4 C at z = 0 is closest to :

The magnetic field of an electromagnetic wave is given by :- \mathop B\limits^ \to = 1.6 \times {10^{ - 6}}\cos \left( {2 \times {{10}^7}z + 6 \times {{10}^{15}}t} \right)\left( {2\mathop i\limits^ \wedge + \mathop j\limits^ \wedge } \right){{Wb} \over {{m^2}}} The associated electric field will be :-

A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is E = 6 V m–1 along y-direction. Its corresponding magnetic field component, B would be :

A light wave is incident normally on a glass slab of refractive index 1.5. If 4 % of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be :

A 27 mW laser beam has a cross-sectional area of 10 mm2. The magnitude of the maximum electric field in this electromagnetic wave is given by : [Given permittivity of space $$\in$$0 = 9 $$\times$$ 10–12 SI units, Speed of light c = 3 $$\times$$ 108 m/s]

An electromagnetic wave of intensity 50 Wm–2 enters in a medium of refractive index 'n' without any loss. The ratio of the magnitudes of electric, and the ratio of the magnitudes of magnetic fields of the wave before and after entering into the medium are respectively, given by:

The electric field of a plane polarized electromagnetic wave in free space at time t = 0 is given by an expression $$\overrightarrow{E}\left(x,y\right)=10\hat{j}\cos \left[\left(6x+8z\right)\right].$$ The magnetic field $$\overrightarrow{B}$$(x,z, t) is given by $$-$$ (c is the velocity of light)

If the magnetic field of a plane electromagnetic wave is given by (the speed of light = 3 × 108 B = 100 × 10–6 sin \left[ {2\pi \times 2 \times {{10}^{15}}\left( {t - {x \over c}} \right)} \right] then the maximum electric field associated with it is -

The energy associated with electric field is (UE) and with magnetic field is (UB) for an electromagnetic wave in free space. Then :

A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point in space and time, $$\overrightarrow{E}=6.3\hat{j}V/m.$$ The corresponding magnetic field $$\overrightarrow{B,}$$ at that point will be :

The mean intensity of radiation on the surface of the Sun is about 108 W/m2 . The rms value of the corresponding magnetic field is closet to :

A block of mass m is kept on a platform which starts from rest with constant acceleration g/2 upward, as shown in figure. Work done by normal reaction on block in time is -

A uniform cable of mass 'M' and length 'L' is placed on a horizontal surface such that its (1/n)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :

A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled 3m is :

A particle which is experiencing a force, given by $$\overrightarrow{F}=3\hat{i}-12\hat{j},$$ undergoes a displacement of $$\overrightarrow{d}=4\overrightarrow{i}$$ particle had a kinetic energy of 3 J at the beginning of the displacement, what is its kinetic energy at the end of the displacement ?