The values of the crystal field stabilization energies for a high spin d6 metal ion in octahedral and tetrahedral fields, respectively, are :

Consider the complex ions, trans-[Co(en)2Cl2]+ (A) and cis-[Co(en)2Cl2]+ (B). The correct statement regarding them is :

For a d4 metal ion in an octahedral field, the correct electronic configuration is :

Complex A has a composition of H12O6Cl3Cr. If the complex on treatment with conc.H2SO4 loses 13.5% of its original mass, the correct molecular formula of A is : [Given: atomic mass of Cr = 52 amu and Cl = 35 amu]

Simplified absorption spectra of three complexes ((i), (ii) and (iii)) of Mn+ ion are provided below; their $$\lambda$$max values are marked as A, B and C respectively. The correct match between the complexes and their $$\lambda$$max values is (i) [M(NCS)6](–6 + n) (ii) [MF6](–6 + n) (iii) [M(NH3)6]n+

The theory that can completely/properly explain the nature of bonding in [Ni(Co)4] is :

The IUPAC name of complex [Pt(NH3)2Cl(NH2CH3)]Cl is:

The number of possible optical isomers for the complexes MA2B2 with sp3 and dsp2 hydridized metal atom. respectively, is : Note : A and B are unidentate netural and unidentate monoanionic ligands, respectively.

Among the statements(a)-(d) the incorrect ones are : (a) Octahedral CO(III) complexes with strong fields ligands have very high magnetic moments. (b) When $$\Delta$$0 < P, the d-electron configuration of Co(III) in an octahedral complex is $$t_{eg}^4{e}_g^2$$ (c) Wavelength of light absorbed by [Co(en)3]3+ is lower than that of [CoF6]3- (d) If the $$\Delta$$0 for an octahedral complex of CO(III) is 18,000 cm-1, the $$\Delta$$t for its tetrahedral complex with the same ligand be 16,000 cm-1

The complex that can show fac- and mer-isomers is :

Among (a) – (d) the complexes that can display geometrical isomerism are : (a) [Pt(NH3)3Cl]+ (b) [Pt(NH3)Cl5]– (c) [Pt(NH3)2Cl(NO2)] (d) [Pt(NH3)4ClBr]2+

The correct order of the calculated spin-only magnetic moments of complexs (A) to (D) is: (A) Ni(CO)4 (B) [Ni(H2O)6]Cl2 (C) Na2[Ni(CN)4] (D) PdCl2(PPh3)2

[Pd(F)(Cl)(Br)(I)]2– has n number of geometrical isomers. Then, the spin-only magnetic moment and crystal field stabilisation energy [CFSE] of [Fe(CN)6]n–6, respectively, are: [Note : Ignore the pairing energy]

Complex X of composition Cr(H2O)6Cln has a spin only magnetic moment of 3.83 BM. It reacts with AgNO3 and shows geometrical isomerism. The IUPAC nomenclature of X is :

The correct order of the spin-only magnetic moments of the following complexes is : (I) [Cr(H2O)6]Br2 (II) Na4[Fe(CN)6] (III) Na3[Fe(C2O4)3] ($$\Delta$$0 $$>$$ P) (IV) (Et4N)2[CoCl4]

The isomer(s) of [Co(NH3)4Cl2] that has/have a Cl–Co–Cl angle of 90°, is/are :

For octahedral Mn(II) and tetrahedral Ni(II) complexes, consider the following statements: (I) both the complexes can be high spin. (II) Ni(II) complex can very rarely be low spin. (III) with strong field ligands, Mn(II) complexes can be low spin. (IV)aqueous solution of Mn(II) ions is yellow in colour. The correct statements are :

Consider that a d6 metal ion (M2+) forms a complex with aqua ligands, and the spin only magnetic moment of the complex is 4.90 BM. The geometry and the crystal field stabilization energy of the complex is

An acidic buffer is obtained on mixing :

Arrange the following solutions in the decreasing order of pOH : (A) 0.01 M HCl (B) 0.01 M NaOH (C) 0.01 M CH3COONa (D) 0.01 M NaCl