Ammonolysis of Alkyl halides followed by the treatment with NaOH solution can be used to prepare primary, secondary and tertiary amines. The purpose of NaOH in the reaction is :
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Hoffmann bromomide degradation of benzamide gives product A, which upon heating with CHCl3 and NaOH gives product B.
The structures of A and B are :
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In the above reaction, the structural formula of (A), ''X'' and ''Y'' respectively are :
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Primary, secondary and tertiary amines can be separated using:
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Considering the above reaction, X and Y respectively are :
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Consider the given reaction, percentage yield of :
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In the reaction of hypobromite with amide, the carbonyl carbon is lost as :
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An organic compound "A" on treatment with benzene sulphonyl chloride gives compound B. B is soluble in dil. NaOH solution. Compound A is :
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The correct structure of Rhumann's Purple, the compound formed in the reaction of ninhydrin with proteins is :
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Compound A is converted to B on reaction with CHCl3 and KOH. The compound B is toxic and can be decomposed by C. A, B and C respectively are :
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In the above reactions, product A and product B respectively are :
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Consider the above reaction, compound B is :
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In the chemical reactions given above A and B respectively are :
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Which one of the following reactions does not occur?
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Given below are two statements, one is labelled as Assertion (A) and other is labelled as Reason (R).
Assertion (A) : Gabriel phthalimide synthesis cannot be used to prepare aromatic primary amines.
Reason (R) : Aryl halides do not undergo nucleophilic substitution reaction.
In the light of the above statements, choose the correct answer from the options given below :
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Which one of the products of the following reactions does not react with Hinsberg reagent to form sulphonamide?
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Consider the above reaction, the product "P" is :
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A reaction of benzonitrile with one equivalent CH3MgBr followed by hydrolysis produces a yellow liquid "P". The compound "P" will give positive _________.
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What is the major product "P" of the following reaction?
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Given below are two statements :
Statement I : Aniline is less basic than acetamide.
Statement II : In aniline, the lone pair of electrons on nitrogen atom is delocalized over benzene ring due to resonance and hence less available to a proton.
Choose the most appropriate option;