For a transistor to act as a switch, it must be operated in

Identify the correct Logic Gate for the following output (Y) of two inputs A and B.

The I-V characteristics of a p-n junction diode in forward bias is shown in the figure. The ratio of dynamic resistance, corresponding to forward bias voltage of 2 V and 4 V respectively, is :

The positive feedback is required by an amplifier to act an oscillator. The feedback here means :

Identify the logic operation performed by the given circuit:

The photodiode is used to detect the optical signals. These diodes are preferably operated in reverse biased mode because :

In the circuit, the logical value of $$A=1$$ or $$B=1$$ when potential at $$A$$ or $$B$$ is $$5\mathrm{V}$$ and the logical value of $$A=0$$ or $$B=0$$ when potential at $$A$$ or $$B$$ is $$0\mathrm{V}$$. The truth table of the given circuit will be :

A logic gate circuit has two inputs A and B and output Y. The voltage waveforms of A, B and Y are shown below. The logic gate circuit is :

For a constant collector-emitter voltage of $$8\mathrm{V}$$, the collector current of a transistor reached to the value of $$6\mathrm{mA}$$ from $$4\mathrm{mA}$$, whereas base current changed from $$20\mu \mathrm{A}$$ to $$25\mu \mathrm{A}$$ value. If transistor is in active state, small signal current gain (current amplification factor) will be :

Identify the solar cell characteristics from the following options :

An n.p.n transistor with current gain $$\beta =100$$ in common emitter configuration is shown in figure. The output voltage of the amplifier will be

The motion of a simple pendulum executing S.H.M. is represented by the following equation. $$y=A\sin (\pi t+\varphi )$$, where time is measured in second. The length of pendulum is

Motion of a particle in x-y plane is described by a set of following equations x = 4\sin \left( {{\pi \over 2} - \omega t} \right)\,m and $$y=4\sin (\omega t)m$$. The path of the particle will be :

The equation of a particle executing simple harmonic motion is given by x = \sin \pi \left( {t + {1 \over 3}} \right)m. At t = 1s, the speed of particle will be (Given : $$\pi$$ = 3.14)

The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is :

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with {g \over 6} vertically upwards then the time period will be : (Where g = acceleration due to gravity)

Two massless springs with spring constants 2 k and 9 k, carry 50 g and 100 g masses at their free ends. These two masses oscillate vertically such that their maximum velocities are equal. Then, the ratio of their respective amplitudes will be :

In figure $$(\mathrm{A})$$, mass '$$2{\mathrm{m}}^{\text{’ }}$$ is fixed on mass '$$\mathrm{m}$$ ' which is attached to two springs of spring constant $$\mathrm{k}$$. In figure (B), mass '$$\mathrm{m}$$' is attached to two springs of spring constant '$$\mathrm{k}$$' and '$$2{\mathrm{k}}^{\prime }$$. If mass '$$\mathrm{m}$$' in (A) and in (B) are displaced by distance '$$x^{\prime }$$ horizontally and then released, then time period $${\mathrm{T}}_1$$ and $${\mathrm{T}}_2$$ corresponding to $$(\mathrm{A})$$ and (B) respectively follow the relation.

When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :

Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located at a height h above the earth surface. Clock - 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of h is - (consider radius of earth $$R_E=6400\mathrm{km}$$ and $$\mathrm{g}$$ on earth $$10\mathrm{m}/{\mathrm{s}}^2$$ )