Mathematicslimits-continuity-and-differentiability2023medium
Mathematicslimits-continuity-and-differentiability2023medium
Let $f, g$ and $h$ be the real valued functions defined on as
and $h(x)=2[x]-f(x)$, where $[x]$ is the greatest integer .
Then the
value of is :
Mathematicslimits-continuity-and-differentiability2023medium
Suppose be a differentiable function such that . If , then \sum_\limits{n=0}^{5} f(n) is equal to :
Mathematicslimits-continuity-and-differentiability2023medium
Let be a root of the equation and f(x) = \left\{ {\matrix{
{{{1 - \cos ({x^2} - 4px + {q^2} + 8q + 16)} \over {{{(x - 2p)}^4}}},} & {x \ne 2p} \cr
{0,} & {x = 2p} \cr
} } \right.
Then , where denotes greatest integer function, is
Mathematicslimits-continuity-and-differentiability2023medium
If the function f(x) = \left\{ {\matrix{
{(1 + |\cos x|)^{\lambda \over {|\cos x|}}} & , & {0
is continuous atx = { \over 2}9\lambda + 6{\log _e}\mu + {\mu ^6} - {e^{6\lambda }}$$ is equal to
Mathematicslimits-continuity-and-differentiability2023medium
The value of \mathop {\lim }\limits_{n \to \infty } {{1 + 2 - 3 + 4 + 5 - 6\, + \,.....\, + \,(3n - 2) + (3n - 1) - 3n} \over {\sqrt {2{n^4} + 4n + 3} - \sqrt {{n^4} + 5n + 4} }} is :
Mathematicslimits-continuity-and-differentiability2023medium
The set of all values of for which , where [] denotes the greatest integer less than or equal to is equal to
Mathematicslimits-continuity-and-differentiability2023medium
\mathop {\lim }\limits_{t \to 0} {\left( {{1^{{1 \over {{{\sin }^2}t}}}} + {2^{{1 \over {{{\sin }^2}t}}}}\, + \,...\, + \,{n^{{1 \over {{{\sin }^2}t}}}}} \right)^{{{\sin }^2}t}} is equal to
Mathematicslimits-continuity-and-differentiability2023medium
Let f(x) = \left\{ {\matrix{
{{x^2}\sin \left( {{1 \over x}} \right)} & {,\,x \ne 0} \cr
0 & {,\,x = 0} \cr
} } \right.
Then at
Mathematicslimits-continuity-and-differentiability2023medium
Let $[x]$ denote the greatest integer function and
. Let $m$ be the number of
points in $[0,2]$, where $f$ is not continuous and $n$ be the number of points in
$(0,2)$, where $f$ is not differentiable. Then is equal to :
Mathematicslimits-continuity-and-differentiability2023hard
If \lim_\limits{x \rightarrow 0} \frac{e^{a x}-\cos (b x)-\frac{cx e^{-c x}}{2}}{1-\cos (2 x)}=17, then is equal to
Mathematicslimits-continuity-and-differentiability2023medium
Let and be two functions defined by
f(x)=\left\{\begin{array}{cc}x+1, & x
Then(g \circ f)(x)$$ is :
Mathematicslimits-continuity-and-differentiability2023medium
Let , where and denotes the greatest integer less than or equal to . Then, is :
Mathematicslimits-continuity-and-differentiability2023medium
If are the roots of the equation , and \lim_\limits{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^{2}+b x+a\right)}{2(1-\alpha x)^{2}}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right), \text { then } \mathrm{k} \text { is equal to } :
Mathematicslimits-continuity-and-differentiability2023medium
\lim_\limits{x \rightarrow 0}\left(\left(\frac{\left(1-\cos ^{2}(3 x)\right.}{\cos ^{3}(4 x)}\right)\left(\frac{\sin ^{3}(4 x)}{\left(\log _{e}(2 x+1)\right)^{5}}\right)\right) is equal to _____________.
Mathematicslimits-continuity-and-differentiability2023medium
Let be positive consecutive terms of an arithmetic progression. If is its common difference, then
\lim_\limits{n \rightarrow \infty} \sqrt{\frac{d}{n}}\left(\frac{1}{\sqrt{a_{1}}+\sqrt{a_{2}}}+\frac{1}{\sqrt{a_{2}}+\sqrt{a_{3}}}+\ldots \ldots \ldots+\frac{1}{\sqrt{a_{n-1}}+\sqrt{a_{n}}}\right) is
Mathematicsinverse-trigonometric-functions2023medium
Let S = \left\{ {x \in R:0
If\mathrm{n(S)}\mathrm{S}$$ then :
Mathematicsinverse-trigonometric-functions2023hard
Let (a, b) be the largest interval for which ,
holds.
If and , then is equal to :
Mathematicsinverse-trigonometric-functions2023medium
Let be the set of all solutions of the equation . Then \sum_\limits{x \in S} 2 \sin ^{-1}\left(x^{2}-1\right) is equal to :
Mathematicsinverse-trigonometric-functions2023medium
If $${\sin ^{ - 1}}{ \over {17}} + {\cos ^{ - 1}}{4 \over 5} - {\tan ^{ - 1}}{{77} \over {36}} = 0,0